1/2y-y/2+y^2=0

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Solution for 1/2y-y/2+y^2=0 equation:



1/2y-y/2+y^2=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
We calculate fractions
y^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{2}=0$

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